Two cylinders A and B of equal capacity are connected to each other via a stopcock. A contains a gas at standard temperature and pressure. B is completely evacuated. The entire system is thermally insulated. The stopcock is suddenly opened. Answer the following:
(a) What is the final pressure of the gas in A and B?
(b) What is the change in internal energy of the gas?
(c) What is the change in the temperature of the gas?
(d) Do the intermediate states of the system (before settling to the final equilibrium state) lie on its P-V-T surface?
Answers
Explanation:
Answer
(a) When the stopcock is suddenly opened, the volume available to the gas at 1 atmospheric pressure will become two times. Therefore, pressure will decrease to one-half, i.e., 0.5 atmosphere.
(b) There will be no change in the internal energy of the gas as no work is done on/by the gas.
(c) Since no work is being done by the gas during the expansion of the gas, the temperature of the gas will not change at all.
(d) No, because the process called free expansion is rapid and cannot be controlled. the intermediate states are non-equilibrium states and do not satisfy the gas equation. In due course, the gas does return to an equilibrium state.
Initially system was at Standard Temperature and Pressure initial pressure of the system would be ,
Let volume of each cylinder is V.
then, total volume = (V + V) = 2V, after stopcock is opened.
as above process is example of free expansion so, temperature doesn't change in whole process. means, it is also an isothermal process. so, we can use Boyle's law,
1atm × V = × 2V
= 1/2 atm = 0.5 atm
hence, final pressure of the gas in A and B is 0.5 atm.