Question

Two cylindrical tanks are connected by a tube with a tap. The radii of the tanks are 7 m and 7/2 m.The water stands to a height 6 m and 5 m respectively. If the tap is opened
find the height to which the water will stand in both the tanks.
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Answer 1

Answer:

Given that diameter of the cylinder d = 7 m

we know that radius r = d/2 = 7/2 = 3.5 m

volume of cylindrical tank is given by

V=\pi r^2hV=πr

2

h

V=3.14 *3.5^2*12 = 461.58V=3.14∗3.5

2

∗12=461.58 cubic metres

Given that side length of the cubical tank = 7 m

We know that volume of cubical tanks is given by

V=x^3V=x

3

where x is the side length of the cube

V=7^3 = 343V=7

3

=343

Other cubical box has also same side length 7 m but the height of water is unknown so let it be x metre.

then volume of the other cubical tank = 7*7*x= 49x

Given that water from cylindrical tank is poured into other two cubical tanks then volume of water in cylinrical tank will be equal to sum of volume of water in both cubical tanks

49x + 343 = 461.58

49x = 461.58 - 343

49x = 118.58

x = 2.42

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