two cylindrical vessels with the distance A and B of area of cross section is 8cmsquare and 320 cmsquare respectively are joined at the bottom by a tube and they are completely filled with water and a mass of 4 Kg is placed on Piston A find the pressure of piston A , the pressure on Piston B and thrust on Piston B
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Let E be the effort applied on the smaller piston A and L be the load required on the larger piston B.
Area of cross section of piston A = 8 cm²
Area of cross section of piston A = 320 cm²
(i) Pressure acting on piston A in the downward direction = Thrust/Area = E/8 cm²
∴Pressure acting on water = E/8 cm² (according to Pascal's Law)
(ii) ∴ Pressure acting on piston B = E/8 cm² (according to Pascal's Law)
(iii) Thrust acting on piston B in the upward direction = Pressure x Area of B
= E x 320 cm²/8 cm²
= 40E
If E is known you can calculate this.
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kvnmurtyGenius
The diagram is missing here. In the diagram the arrangement would be clearer.
The pistons are exposed to the atmosphere. So atmospheric pressure acts on them. It is equal to 1.013 * 10⁵ Pa or N/m² or 1.013 * 10 dynes/cm²
As the pistons are both in static equilibrium, the pressure from the water is equal to the atmospheric pressure. So pistons are balanced. We assume that the pistons are weightless. (otherwise we need to add their weight to the pressure/thrust).
As the two cylindrical vessels are connected, water flows between them to equalize pressure at the same height or altitude. Thrust force is the force acting on the piston perpendicular to the surface area.
Pressure by water on Piston A or piston B = 10.13 dynes/cm²
Thrust force
= pressure * area of cross section
= 10.13 * 8 = 81.04 dynes for Piston A
and
= 10.13 * 320 = 3, 241.60 dynes for piston B
(1 dyne = 10⁻⁵ N)
Area of cross section of piston A = 8 cm²
Area of cross section of piston A = 320 cm²
(i) Pressure acting on piston A in the downward direction = Thrust/Area = E/8 cm²
∴Pressure acting on water = E/8 cm² (according to Pascal's Law)
(ii) ∴ Pressure acting on piston B = E/8 cm² (according to Pascal's Law)
(iii) Thrust acting on piston B in the upward direction = Pressure x Area of B
= E x 320 cm²/8 cm²
= 40E
If E is known you can calculate this.
CommentsReport
5.0
2 votes
THANKS
4
kvnmurtyGenius
The diagram is missing here. In the diagram the arrangement would be clearer.
The pistons are exposed to the atmosphere. So atmospheric pressure acts on them. It is equal to 1.013 * 10⁵ Pa or N/m² or 1.013 * 10 dynes/cm²
As the pistons are both in static equilibrium, the pressure from the water is equal to the atmospheric pressure. So pistons are balanced. We assume that the pistons are weightless. (otherwise we need to add their weight to the pressure/thrust).
As the two cylindrical vessels are connected, water flows between them to equalize pressure at the same height or altitude. Thrust force is the force acting on the piston perpendicular to the surface area.
Pressure by water on Piston A or piston B = 10.13 dynes/cm²
Thrust force
= pressure * area of cross section
= 10.13 * 8 = 81.04 dynes for Piston A
and
= 10.13 * 320 = 3, 241.60 dynes for piston B
(1 dyne = 10⁻⁵ N)
adhyan3:
the answer is not matching with thw booms answer there is no diagram as the question is written in the book i asked you plzz help me
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