two dealers have marked and articles in the same price the first De Los two successive discount of 15% of 5% The Other allows a discount of 20% which is the best offer
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Answer:
Solution:
Two dealers have marked an article for same price. The first dealer allows, two successive discounts of 15% and 5%. The other allows a discount of 20%.
Now:
Let the marked price (MP) be Rs. x.
So,
The selling price (SP) of the first dealer:
SP = (1-d/100) (1-d/100) * MP
SP = (1-15/100) (1-5/100)
SP = 85/100 * 95/100 * x
SP = 17/20 * 19/20 * x
SP = 323/400x
Now,
Selling price (SP) of the second dealer:
SP = (1-d/100) * MP
SP = (1-20/100) * x
SP = 80/100x
SP = 4/5x
Now, we know that:
SP of 1st dealer > SP of 2nd dealer
Hence:
Second option is better.
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Step-by-step explanation:
by Wizardaditya 04.10.2017
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SP. = (1-r1/100)*(1-r2/100)*MP
= (1-15/100)*(1-5/100)*Rs.x
= (17/20)*(19/20)*Rs.x
= Rs.383x/400
For the second dealer-
SP. = (1-r/100)*MP
= (1-20/100)*Rs.x
= Rs.4x/5
SP of 1st dealer >SP of second dealer
Rs.383/400 > Rs. 4x/5
Difference of both the offers = Rs.383x/400- Rs.4x/5
= Rs.83x/400