Math, asked by dinesh85479, 11 months ago

two dealers have marked and articles in the same price the first De Los two successive discount of 15% of 5% The Other allows a discount of 20% which is the best offer​

Answers

Answered by js403730
2

Answer:

Solution:

Two dealers have marked an article for same price. The first dealer allows, two successive discounts of 15% and 5%. The other allows a discount of 20%.

Now:

Let the marked price (MP) be Rs. x.

So,

The selling price (SP) of the first dealer:

SP = (1-d/100) (1-d/100) * MP

SP = (1-15/100) (1-5/100)

SP = 85/100 * 95/100 * x

SP = 17/20 * 19/20 * x

SP = 323/400x

Now,

Selling price (SP) of the second dealer:

SP = (1-d/100) * MP

SP = (1-20/100) * x

SP = 80/100x

SP = 4/5x

Now, we know that:

SP of 1st dealer > SP of 2nd dealer

Hence:

Second option is better.

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Answered by bhanuprakashreddy23
0

Step-by-step explanation:

by Wizardaditya 04.10.2017

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Answers

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SP. = (1-r1/100)*(1-r2/100)*MP

= (1-15/100)*(1-5/100)*Rs.x

= (17/20)*(19/20)*Rs.x

= Rs.383x/400

For the second dealer-

SP. = (1-r/100)*MP

= (1-20/100)*Rs.x

= Rs.4x/5

SP of 1st dealer >SP of second dealer

Rs.383/400 > Rs. 4x/5

Difference of both the offers = Rs.383x/400- Rs.4x/5

= Rs.83x/400

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