Question

two decimals whose sum is between 0.5 and 0.6

Answer 1

Answer:

0.2 and 0.35 are among the decimals whose sum is between 0.5 and 0.6. Their sum is 0.55

Answer 2

Answer:

Required two numbers are 0.2 and 0.35

Step-by-step explanation:

Here given two decimal numbers are 0.5 and 0.6.

According to number line a number between 0.5 and 0.6 is 0.55

We can write,

$0.2 + 0.35 = 0.55$

So, required two numbers are 0.2 and 0.35

This is a problem of decimal part of Mathematics.

Some important Mathematics formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

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