Question

Two devices of rating 44W,200 V and 11W,220 V are connected in series. the combination is connected across a 440W mains. the fuse of which of the two devices is likely to burn when the switch is ON.? justify your answer

Answer 1

I dontttt knowwwwwwwww

Answer 2

229.95 V across the device of 11 W, 220 V ratting is sufficient to burn the fuse of device

Explanation:

given data

devices 1 power = 44 W

voltage = 200 V

devices 2 power = 11 W

voltage = 220 V

solution

we know that here Resistance that is express as

Resistance R = $\frac{V^2}{W}$  ......................1

put here value for both device

device 1 Resistance R = $\frac{200^2}{44}$

device 1 Resistance R =  909.09

device 2 Resistance R = $\frac{220^2}{11}$

device 2 Resistance R = 1100

connected in series

so current will be

current I = $\frac{V}{R}$  

current I = \frac{220+200}{1100+909.09}

current I = 0.209

so

voltage across device 1 = I × R

voltage across device 1 = 0.209 × 909.09 = 189.99

voltage across device 2 = I × R

voltage across device 2 = 0.209 × 1100 = 229.95

so here 229.95 V across the device of 11 W, 220 V ratting is sufficient to burn the fuse of device

Learn more  :

which devices is likely to burn when the switch is ON

1. https://brainly.in/question/2844990