Question

two diagonal of a rombus are 18cm 24cm find its perimeter​

Answer 1

Answer:

Answer. Answer: Since the length of all sides of a rhombus are equal, Perimeter =4× length of one side =4×15=60cm

Answer 2

Answer:

Side           =  a = 15cm

Perimeter  =  P = 60cm

Area           = A = 216$cm^{2}$

Step-by-step explanation:

Consider a rhombus of side ABCD

The diagonal of a rhombus bisect each other at 90 degrees, So they will form four right angled triangle

In right angled triangle AOD, we can apply Pythagoras theorem

$AD^{2}$ = $AO^{2}$+$OD^{2}$

        =$9^{2}$+$12^{2}$

∴$AD^{2}$   =225

∴AD   = 15cm    

Similarly, AB=BC=CD=15cm

∴length of side of a rhombus = a = 15cm

Perimeter of rhombus = P = 4a

P = 4(15)

∴P = 60 cm

∴Perimeter of rhombus is 60cm  

Area of rhombus = $\frac{1}{2}$ x d1 x d2

                            =$\frac{1}{2}$ x 18 x 24

                            =216$cm^{2}$

Area of rhombus is 216$cm^{2}$