Question

Two diagonally opposite corners of a square made of a four thin rods of same material same dimensions are st temperature 40°C and 10°C.if only heat conduction takes placr thrn the temperature difference between otger two corners will be

Answer 1

The temperature difference between other two corners will be 0°C.

Explanation:

Let end "A be at temperature 40°C  and end "B" at temperature  10°C.

End "B" at temperature = T1°C

End "A" at temperature = T2°C

Now let thermal resistance of each wire = R

Now we have

40 - T1/R = T1 - 10/R

2T1 = 40 + 10

T1 = 50°C/2

T1 = 25°C

Again we have

40 - T2 / R = T2 - 10/R

T2 = 50°C/2 = 25 °C

Now

T2 - T1 = 25°C - 25°C = 0 °C

Thus the temperature difference between other two corners will be 0°C.

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Answer 2

The temperature difference between other two corners will be 0°C.

Explanation:

Let end "A be at temperature 40°C  and end "B" at temperature  10°C.

End "B" at temperature = T1°C

End "A" at temperature = T2°C

Now let thermal resistance of each wire = R

Now we have

40 - T1/R = T1 - 10/R

2T1 = 40 + 10

T1 = 50°C/2

T1 = 25°C

Again we have

40 - T2 / R = T2 - 10/R

T2 = 50°C/2 = 25 °C

Now

T2 - T1 = 25°C - 25°C = 0 °C

Thus the temperature difference between other two corners will be 0°C