Question

Two diagonals of a rhombus are 72 cm and 30 cm respectively. What is its perimeter? ( A ) 144 cm ( B ) 145 cm ( C ) 156 cm ( D ) 135 cm

Answer 1

Given:

The two diagonals of a rhombus are 72 cm and 30 cm respectively. What is its perimeter?

To find:

What is its perimeter?

Solution:

To solve the above-given problem we will use the following formula of the perimeter of a rhombus:

$\boxed{\bold{Perimeter\:of\:a\:rhombus = 2 \sqrt{d_1^2 +d_2^2} }}$

where $d_1 = diagonal \:1$ and $d_2 = diagonal \:2$

Here we have,

The length of the diagonal 1 = 72 cm

The length of the diagonal 2 = 30 cm

Now, on substituting the given values of the length of the two diagonals of the rhombus into the above formula of the perimeter, we get

The perimeter of the rhombus is,

= $2 \sqrt{72^2 +30^2}$

= $2 \sqrt{5184 +900}$

= $2 \sqrt{6084}$

= $2 \times 78$

= $\bold{156\:cm}$ ← option (C)

Thus, the perimeter of the rhombus is → 156 cm.

------------------------------------------------------------------------------------------------

Also View:

The perimeter of a rhombus is 4m. One of its diagonal is 4/3rd of the other. Find the area of the rhombus.

brainly.in/question/23659246

Find the perimeter of a rhombus with diagonals 30 cm and 40 cm long

brainly.in/question/2011995