Question

TWO DIAGONALS OF RECTANGLE ARE [3X +2 ] CM AND [2X +3] CM FIND THE MEASURE MENTS OF DIAGONALS

Answer 1

Answer:

5 cm

Step-by-step explanation:

We know that the diagonals of a rectangle are equal.

So,

[3x+2]cm=[2x+3]cm

⇒ 3x-2x=3-2

⇒x=1

∴Length of diagonals = [3x+2]cm =[2x+3] cm =5 cm

Hope this helps you.

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Answer 2

GIVEN :-

• Diagonal of rectangle d1 = (3x + 2) cm.
• Diagonal of rectangle d2 = (2x + 3) cm.

TO FIND :-

• The measurement of the diagonals.

SOLUTUON :-

★ As we know that one of the property of triangle that the diagonals of rhombus are equal and bisect each other at 90°.

$\\ : \implies \displaystyle \sf \: Diagonal \: (d_{1}) = Diagonal \: (d_{2})$

$: \implies \displaystyle \sf \:(3x + 2) = (2x + 3)$

$: \implies \displaystyle \sf \:3x - 2x = 3 - 2$

$: \implies\underline{ \boxed{\displaystyle \sf \:x = 1}}$

_________________________

$\\ \dashrightarrow \: \displaystyle \sf \: Diagonal \: (d_{1}) = 3x + 2$

$\dashrightarrow \: \displaystyle \sf \: Diagonal \: (d_{1}) = \:3 \times 1 + 2$

$\dashrightarrow \: \displaystyle \sf \: Diagonal \: (d_{1}) =3 + 2$

$\dashrightarrow \: \underline{ \boxed{ \displaystyle \sf \: Diagonal \: (d_{1}) =5cm}}$

______________________

$\\ \dashrightarrow \: \displaystyle \sf \: Diagonal \: (d_{2}) = 2x + 3$

$\dashrightarrow \: \displaystyle \sf \: Diagonal \: (d_{2}) = \:2 \times 1 + 3$

$\dashrightarrow \: \displaystyle \sf \: Diagonal \: (d_{2}) =2+ 3$

$\dashrightarrow \: \underline{ \boxed{ \displaystyle \sf \: Diagonal \: (d_{2}) =5cm}}$

$\therefore\underline {\displaystyle\sf Diagonals \ of \ rectangle \: is \: 5 \: cm \: each.}$