two diameter of a circle intersect each other at right angle.prove that the quadrilaeral formed by joining their end points in a square
Answers
Answered by
2
also /_ABC=/_DAB=/_ADC=/_DCB=90° (angle in a semicircle)
=>ABCD is a square
=>ABCD is a square
Attachments:
Mohit0:
ur welcome
Similar questions