Question

Two diameters of a circle intersect each other at
Langles. Prove that the quadrilaterals foomed by joints
their end points is á square​

Answer 1

Step-by-step explanation:

Let AB and CD be the diagonals of a circle such that AB⊥CD

Joining points A,b,C,D in order we see that AB and CD are the equal diagonals of quad. ACBD which intersect at rightangle.

∴ ACBD is a square.

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