Two dice are numbered 1, 2, 3, 4, 5, 6 and 1, 1, 2, 2, 3, 3 respectively. They are thrown and the sum of the numbers on them is noted. Find the probability getting each sum from 2 to 9 separately
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72
Answer:
Favorable outcomes 36
(1,1) (2,1) (3,1) (4,1) (5,1) (6,1)
(1,1) (2,1) (3,1) (4,1) (5,1) (6,1)
(1,2) (2,2) (3,2) (4,2) (5,2) (6,2)
(1,2) (2,2) (3,2) (4,2) (5,2) (6,2)
(1,3) (2,3) (3,3) (4,3) (5,3) (6,3)
(1,3) (2,3) (3,3) (4,3) (5,3) (6,3)
SUM OF 2=1/18
SUM OF 3 = 1/9
SUM OF 4 = 1/9
SUM OF 5 = 1/6
SUM OF 6 = 1/6
SUM OF 7 = 2/9
SUM OF 8 = 1/9
SUM OF 9 = 1/18
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19
Step-by-step explanation:
total outcomes-36
probabilities of sum from 2 to 9
sum of 2- 1/18
sum of 3-1/9
sum of 4-1/6
sum of 5-1/6
sum of 6-1/6
sum of 7-1/6
sum of 8-1/9
sum of 9-1/18
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