Question

Two dice are numbered 1, 2, 3, 4, 5, 6 and 1, 1, 2, 2, 3, 3 respectively. They are thrown and the sum of the numbers on them is noted. Find the probability getting each sum from 2 to 9 separately

Answer 1

Answer:

Favorable outcomes 36

(1,1) (2,1) (3,1) (4,1) (5,1) (6,1)

(1,1) (2,1) (3,1) (4,1) (5,1) (6,1)

(1,2) (2,2) (3,2) (4,2) (5,2) (6,2)

(1,2) (2,2) (3,2) (4,2) (5,2) (6,2)

(1,3) (2,3) (3,3) (4,3) (5,3) (6,3)

(1,3) (2,3) (3,3) (4,3) (5,3) (6,3)

SUM OF 2=1/18

SUM OF 3 = 1/9

SUM OF 4 = 1/9

SUM OF 5 = 1/6

SUM OF 6 = 1/6

SUM OF 7 = 2/9

SUM OF 8 = 1/9

SUM OF 9 = 1/18

Hope it is helpful

This is the perfect answer

Step-by-step explanation:

Answer 2

Step-by-step explanation:

total outcomes-36

probabilities of sum from 2 to 9

sum of 2- 1/18

sum of 3-1/9

sum of 4-1/6

sum of 5-1/6

sum of 6-1/6

sum of 7-1/6

sum of 8-1/9

sum of 9-1/18