Question

Two dice are numbered 1, 2, 3, 4, 5, 6 and 1, 1, 2, 2, 3, 3, respectively. They are thrown, and the sum of the numbers on them is noted. Find the probability of getting each sum from 2 to 9 separately.


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Answer 1

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Favorable outcomes 36

(1,1) (2,1) (3,1) (4,1) (5,1) (6,1)

(1,1) (2,1) (3,1) (4,1) (5,1) (6,1)

(1,2) (2,2) (3,2) (4,2) (5,2) (6,2)

(1,2) (2,2) (3,2) (4,2) (5,2) (6,2)

(1,3) (2,3) (3,3) (4,3) (5,3) (6,3)

(1,3) (2,3) (3,3) (4,3) (5,3) (6,3)

➠ Sum of 2=1/18

➠ Sum of 3 = 1/9

➠ Sum of 4 = 1/9

➠ Sum of 5 = 1/6

➠ Sum of 6 = 1/6

➠ Sum of 7 = 2/9

➠ Sum of 8 = 1/9

➠ Sum of 9 = 1/18

Answer 2

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Favourable outcomes =36

(1,1)

(2,1)

(3,1)

(4,1)

(5,1)

(6,1)

(1,1)

(2,1)

(3,1)

(4,1)

(5,1)

(6,1)

(1,1)

(2,2)

(3,2)

(4,2)

(5,2)

(6,2)

(1,2)

(2,2)

(3,2)

(4,2)

(5,2)

(6,2)

(1,3)

(2,3)

(3,3)

(4,3)

(5,3)

(6,3)

(1,3)

(2,3)

(3,3)

(4,3)

(5,3)

(6,3)

Sum of 2=1

18

Sum of 3=1

9

Sum of 4 =1

9

Sum of 5=1

6

Sum of 6=1

6

Sum of 7=2

9

Sum of 8=1

9

Sum of 9=1

18

May This Helps you .