Question

two dice are numbered 1,2,3,4,5,6 and 1,1,2,2,3,3 respectively . they are thrown and the sum of the numbers on them is noted . find the probability of getting each sum fr 2 to 9 separately​

Answer 1

ANSWER :

Favourable outcomes =36

(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)

(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)

(1,1)(2,2)(3,2)(4,2)(5,2)(6,2)

(1,2)(2,2)(3,2)(4,2)(5,2)(6,2)

(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)

(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)

the probability of getting each sum from 2 to 9

Sum of 2=2/36=1/18

Sum of 3=4/36=1/9

Sum of 4=4/36=1/9

Sum of 5=6/36=1/6

Sum of 6=6/36=1/6

Sum of 7=6/36=1/6

Sum of 8=4/36=1/9

Sum of 9=2/36=1/18