Two dice are numbered 1,2,3,4,5,6 and 1,1,2,2,3,3 Respectively. They are thrown and the sum of the numbers on them is noted. Find the probability of getting each sum from 2 to 9 separately.
Answers
Answered by
1
Favourable outcomes =36
(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)
(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)
(1,1)(2,2)(3,2)(4,2)(5,2)(6,2)
(1,2)(2,2)(3,2)(4,2)(5,2)(6,2)
(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)
(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)
the probability of getting each sum from 2 to 9
Sum of 2= 2/36 =1/18
sum of 9= 2/36 =1/18
Similar questions