Two dice are numbered 1,2,3,4,5,6 and 1,1,2,2,3,3 respectively. They are thrown and the sum of the numbers on them is noted. Find the probability of getting each sum from 2 to 9 respectively.
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1,1 1,2 1,3 2,1 2,2 2,3 3,1 3,2 3,3 4,1 4,2 4,3 5,1 5,2 5,3 6,1 6,2 6,3
total 16 chances and total no.of out comes =6!/3! = 720/6 =120
probability= 16/120
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Virendersingh7:
please please mark on brain list
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ans is 4/36
2/36 2/36
2/36 2/36
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Can u please do separately of each from 2 to 9 and send(read the question properly, they said 2 to 9 each respectively).... PLZ....
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