Two dice are numbered 1,2,3,4,5,6 and 1,2,2,3,3,4 respectively.
They are thrown and the sum of numbers on them is noted.
Find the probability of getting sum atmost 3 .
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Answer:
Favourable outcomes =36
(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)
(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)
(1,1)(2,2)(3,2)(4,2)(5,2)(6,2)
(1,2)(2,2)(3,2)(4,2)(5,2)(6,2)
(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)
(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)
the probability of getting each sum from 2 to 9
Sum of 2=
36
2
=
18
1
Sum of 3=
36
4
=
9
1
Sum of 4=
36
4
=
9
1
Sum of 5=
36
6
=
6
1
Sum of 6=
36
6
=
6
1
Sum of 7=
36
6
=
6
1
Sum of 8=
36
4
=
9
1
Sum of 9=
36
2
=
18
1
.
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