Question

two dice are rolled
a prime no. on each dice​

Answer 1

(2,2)

(2,3)

(2,5)

(3,2)

(3,3)

(3,5)

(5,2)

(5,3)

(5,5)

Hence the probability is $<frac>{9}{36}</frac>$

= 1/4

Answer 2

Total no on two dice = 36

Events of getting prime no = 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31,

Total no of prime nos = 11

Therefore,

Probability of getting prime no = $\frac{11}{36}$ = $\frac{11}{36}$

$\bold{Hope \: it \: helps....}$