two dice are rolled, find the probability that the sum is less than 13
Answers
Answered by
12
Answer:
36/36=1
Step by step explanation:
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
=36
So,the number of favourable outcomes=36
And the number of total outcomes =36
Hope it helps.....
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ghostrider2102:
And you
Answered by
11
Answer:
Step-by-step explanation:
Two dice are rolled so following chances are their
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
Total out comes 36
So the probability of getting sum less than 13 is
36/36=1 it means it is a sure outcome
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