Question

Two dice are rolled. Find the probability that the sum of outcomes is i) equal to 4
ii) greater than 10 iii)less than 13.​

Answer 1

Step-by-step explanation:

n(s) = 6*6 = 36

n(sum equal to four) = {(1,3),(3,1),(2,2)}

=3

P(getting sum as 4) = 3/36 = 1/12

n(sum greater than 10) = {(5,6),(6,5),(6,6)}

= 3

so probability is again 1/12

as the highest number possible is 12 and we need number less than 13 which means any number is acceptable so the probability is 1

36/36 =1