Question

Two dice are rolled once find the probability of getting such no. On two dice whose product is a perfect square

Answer 1

Perfect squares between 1 and 12: 4 and 9

Probability for 4 = (1,3),(2,2),(3,1)  =  3

Probability for 9 = (3,3)(6,6)(5,4)(4,5)   =  4

the probability of square of 4 and 9 = 3 +4

                                                            = 7


the probability of getting perfect square = 7/36

Answer 2

Answer:

Step-by-step explanation:

The total number of dice thrown = 2.

Favorable outcomes n(S) = 6^2

                                          = 36.

Let A be the event of getting the product is a perfect square.

n(A) = {1,1},{1,4},{2,2},{3,3},{4,1},{4,4},{5,5},{6,6}

       = 8.

Therefore required probability p(A) = n(A)/n(S)

                                                           = 8/36

                                                           = 2/9.