Two dice are rolled once. Find the probability of getting such numbers on two dice, whose product is a perfect square.
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Answered by
18
The total number of dice thrown = 2.
Favorable outcomes n(S) = 6^2
= 36.
Let A be the event of getting the product is a perfect square.
n(A) = {1,1},{1,4},{2,2},{3,3},{4,1},{4,4},{5,5},{6,6}
= 8.
Therefore required probability p(A) = n(A)/n(S)
= 8/36
= 2/9.
Hope this helps!
Favorable outcomes n(S) = 6^2
= 36.
Let A be the event of getting the product is a perfect square.
n(A) = {1,1},{1,4},{2,2},{3,3},{4,1},{4,4},{5,5},{6,6}
= 8.
Therefore required probability p(A) = n(A)/n(S)
= 8/36
= 2/9.
Hope this helps!
siddhartharao77:
:-)
Answered by
1
Answer:
Step-by-step explanation:
probability=total no. of favourable outcomes/no. of given outcomes
your answer is-
8/36 .
THANK YOU.
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