Question

two dice are rolled once . Find the probability of getting the sum of doublets less than 5

Answer 1

Answer:p(getting doublets less than 5) = 2/36 or 1/18

Step-by-step explanation:total no of outcome are 36 as dice are 2 so 6^2 = 36

Possible outcome = 2

1,1 or 2,2

So probability = possible outcome/total no of outcome

Hence 2/36 or 1/18

Hope it helps

Thanks

Answer 2

The probability of getting the sum of doublets less than 5 is 1/6

Given : Two dice are rolled once

To find : The probability of getting the sum of doublets less than 5

Solution :

Step 1 of 3 :

Find total number of possible outcomes

Two dices are thrown

So possible outcomes are

= { (1,1), (1,2), (1,3), (1,4),(1,5),(1,6),(2,1), (2,2), (2,3), (2,4),(2,5),(2,6),(3,1), (3,2), (3,3), (3,4),(3,5),(3,6),(4,1), (4,2), (4,3), (4,4),(4,5),(4,6),(5,1), (5,2), (5,3), (5,4),(5,5),(5,6),(6,1), (6,2), (6,3), (6,4),(6,5),(6,6)}

So the total number of possible outcomes = 36

Step 2 of 3 :

Find number of possible outcomes for the event

Let A be the event that of getting the sum of doublets less than 5

Then three cases arises

1. When Sum of doublets is 2 then possible outcomes are (1,1)

2. When Sum of doublets is 3 then possible outcomes are (1,2) , (2,1)

3. When Sum of doublets is 4 then possible outcomes are (1,3) , (2,2) , (3,1)

So total number possible outcomes for the event A is 6

Step 3 of 3 :

Find the probability

Hence the required probability

= P(A)

$\displaystyle \sf{ = \frac{Number \: of \: favourable \: cases \: to \: the \: event \: A }{Total \: number \: of \: possible \: outcomes }}$

$\displaystyle \sf{ = \frac{6}{36} }$

$\displaystyle \sf{ = \frac{1}{6} }$

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