Two dice are rolled once simultaneously. Find the probability that the sum of the numbers on
the top of the dice is a perfect square.
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Answer: 7/36
Explanation:
Possible outcomes =
(1,1) , (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
Total number of possible outcomes = 36
Favourable outcomes =
(1,3), (2,2), (3,1), (3,6), (4,5), (5,4), (6,3)
Number of favourable outcomes = 7
P(sum of the numbers is a perfect square)
= No. of favourable outcomes / Total number of possible outcomes
= 7/36
Hope you understood.
Thank You.
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