Two.dice are rolled once. what is.the probability of getting a number on the two dice whose product is 6
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here's you answer:
Sample space of two dice =
{(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}
Event space of the event = { (1,6),(2,3),(3,2),(6,1)}
n(s)=36,n(E)=4
therefore probability of event = n(E) ÷ n(s)
=4÷36
=1/9
Sample space of two dice =
{(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}
Event space of the event = { (1,6),(2,3),(3,2),(6,1)}
n(s)=36,n(E)=4
therefore probability of event = n(E) ÷ n(s)
=4÷36
=1/9
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