Question

Two dice are rolled simultaneously .find probability
of a) getting a sum of 5 (b) getting a number
such that one is double of other​

Answer 1

Step-by-step explanation:

WHEN WE DICE ROLLED TWICE WE GET FOLLOWING OUTCOMES

S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3)(6,4),(6,5),(6,6)}

n(S) = 36

SUPPOSE 'A' IS THE EVENT THAT SHOWS GETTING A SUM OF 5

A = {(1,4),(2,3),(3,2),(4,1)}

n(A) = 4

SO..

P(A) = n(A) / n(S)

P(A) = 4/36

P(A) = 1/9

SUPPOSE 'B' IS THE EVENT THAT SHOWS GETTING A NUMBER THAT ONE IS DOUBLE OF OTHER

B = {(1,2),(2,4),(3,6)}

n(B) = 3

SO..

P(B) = n(B) /n(S)

P(B) = 3/36

P(B) = 1/12

I HOPE THIS IS HELPFUL TO YOU