Question

Two dice are rolled simultaneously.Find the probability:

Obtaining a total of at least 9.

Answer 1

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When, two dice are rolled simultaneously;
the total number of possible outcomes

=6×6 =36

For obtaining a total of at least 9;

the favorable outcomes are :-

(3,6),(4,5),(4,6),(5,4),(5,5),(5,6),(6,3),(6,4),(6,5) and (6,6)

=> No. of favorite outcomes =10.

Therefore,

=> Required probability= 10/36 = 5/18.

Answer = 5/18.

Thanks❤️

Answer 2

When two dies are rolled,

All possible outcomes = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

No. of possible outcomes= 36

All favourable outcomes={(3,6),(4,5),(4,6),(5,4),(5,5),(5,6),(6,3),(6,4),(6,5),(6,6)}

No. of favourable outcomes=10

So, probability of obtaining a total of at least 9=No. of favourable outcomes/Total no. of possible outcomes

=10/36=5/18

So, probability is 5/18.