Question

Two dice are rolled simultaneously. Find the probability (a) of event A that the
sum of the digits on the upper faces is a prime number. (b) of event B that the sum
of the digits on the upper faces is a multiple of 5.​

Answer 1

Answer:

mark me a

branest

hlohlibhlvsnsgeksbdvdhjevdhejebd

Answer 2

Answer:

$$ \begin{array}{l}Sample \ space (s)=\left\{(1,1)(1,2)(1,3)(1,4)(1,5)(1,6) \\ (2,1)(2,2)(2,3)(2,4)(2,5)(2,6) \\ (3,1)(3,2)(3,3)(3,4)(3,5)(3,6) \\ (4,1)(4,2)(4,3)(4,4)(4,5)(4,6) \\ (5,1)(5,2)(5,3)(5,4)(5,5)(5,6) \\ (6,1)(6,2)(6,3)(6,4)(6,5)(6,6)\right\} \end{array} $$

∴n(S)=36

Event A: sum of the digits on the upper faces is at least 10A={(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)}

∴n(A)=6

∴P(A)=

n(S)

n(A)

=

36

6

=

6

1

Hence, the probability that the sum of the digits on the upper faces is at least 10 is =

6

1

A