Question

Two dice are rolled simultaneously. Find the probability of getting: sum of numbers as a multiple of 2

Answer 1

Answer:

1,1 1,3 1,5 2,2 2,4 2,6 3,1 3,3 3,5 4,2 4,4 4,6 5,1 5,3 5,5 6,2 6,4 6,6

Answer 2

Answer:

The probability of getting the sum of numbers as a multiple of 2 is 0.5

Step-by-step explanation:

Let S be the sample set. Since two dice are rolled, the sample set will be as follows:

S = { (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) }

n(S) = 36

We have to find the probability of getting the sum of numbers as a multiple of 2.

Let A be the set where the sum of the numbers on the dice is a multiple of 2. Then,

A = { (1, 1), (1, 3), (1, 5), (2, 2), (2, 4), (2, 6), (3, 1), (3, 3), (3, 5), (4, 2), (4, 4), (4, 6), (5, 1), (5, 3), (5, 5), (6, 2), (6, 4), (6, 6) }

n(A) = 18

We know that the probability of a set is given by dividing the number of elements in the set by the number of elements in the sample set.

Therefore,

$P(A) = \frac{n(A)}{n(S)}$

$P(A) = \frac{18}{36}$

$P(A) = \frac{1}{2}$

P(A) = 0.5

Therefore, the probability is getting the sum of numbers as a multiple of 2 is 0.5

#SPJ2