Question

two dice are rolled simultaneously . find the probability of : getting a multiple of 4 on the one dice and 3 on the other dice , and getting a sum of multiple of 3​

Answer 1

Answer:

Step-by-step explanation:

n(S)=6x6=36

1) let A be the event getting 4 on the one dice and 3 on the other dice

    A={ (4,3),(3,4) }

   n(A)=2

∴P(A)=n(A)/n(S)

∴p(A)=2/36

∴p(A)=1/18

2) Let B be the event getting sum of multiple of 3

  B={ (1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3),(6,6) }                     n(B)= 12

∴P(B)=n(B)/n(S)

∴P(B)=12/36

∴P(B)=1/3

Hope it will help u...