Question

Two dice are rolled simultaneously. Find the probability of getting a sum greater

than 6 that is a multiple of 3.​

Answer 1

Answer:

the outcomes are

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

Step-by-step explanation:

favourable outcomes are={(4,6);(4,5);(5,4);(6,3);(6,6)}

P(E)

$= \frac{no. \: of \: favourable \: outcome}{total \: no. \: of \: outcome} \\ = \frac{5}{36}$