Question

Two dice are rolled simultaneously find the probability of getting a sum which is a multiple of 3

Answer 1

Answer:

When two dice are rolled, we have n(S) = (6 6) = 36.

getting

a multiple of 3 as the sum:

Let

E8 = event of getting a multiple of 3 as the sum. The events of a multiple of 3

as the sum will be E8 = [(1, 2), (1, 5), (2, 1), (2, 4), (3, 3), (3, 6), (4,

2), (4, 5), (5, 1), (5, 4), (6, 3) (6, 6)] = 12

Therefore,

probability of getting a multiple of 3 as the sum

P(E8)=

Totalnumberofpossibleoutcome

Numberoffavorableoutcomes

=12/36

=1/3

Answer 2

1 / 3 pls mark as brilliant