Question

Two dice are rolled simultaneously.find the probability of getting 9 as sum of number on both the dice. ​

Answer 1

$hello \: mate$

Possible outcomes:

➡(1, 1) , (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1) , (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1) , (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1) , (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1) , (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1) , (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Favourable outcomes= (6,3),(4,5),(5,4),(3,6)

P(getting 9 as sum of number)=4/36

➡1/9

Answer 2

S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

n(S)=36

consider probability as event A

A={(3,6),(4,5),(5,4),(6,3)}

n(A)=4

p(A)=n(A)/n(S)

p(A)= 4/36
=1/9

therefore probability of getting 9 as a sum of number on both the dice is 1/9

hopefully it will help you a lot..

Thank you for your question..