Two dice are rolled simultaneously find the probability that the sum of the two nmbers appearing on their tops is less than or equal to 10
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Here the number of possible outcomes n(S)=6×6=36
As all the outcomes are favorable to the event E, Sum of two numbers is less than or equal to 10,
So, P (E)= 33/36 = 11/12
Hope it helps.. thank you.
As all the outcomes are favorable to the event E, Sum of two numbers is less than or equal to 10,
So, P (E)= 33/36 = 11/12
Hope it helps.. thank you.
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