two dice are rolled simultaneously find the probability that the sum of numbers appearing is 10
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Answered by
13
Answer:
Step-by-step explanation
Total no. of possible outcome= 36
Total no.of favourable events = 3
P(E)= 3/36
= 1/12.
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john8790:
is this correct
Answered by
6
Answer:
Step-by-step explanation:
if two dice are thrown simultaneously.....
then...
sample space =36
n(s)=36
let event A =sum of numbers appearing is 10
A = 3
therefore,
p(A) =n(A) /n(S)
=3 /36
= 1 /12
therefore probability is 1 /12
hope it helps ...
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