Two dice are rolled together. Find the probability of getting
i) a sum of 7 ii) a sum greater than 10 .
please help me
Answers
Step-by-step explanation:
Sample space for total number of possible outcomes
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
Total number of outcomes
=
36
Favorable outcomes for sum greater than 10 are
(5,6),(6,5),(6,6)
Number of favorable outcomes
=
3
Favorable outcomes for sum less than 5 are
(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)
Number of favorable outcomes
=
6
Hence, the probability of obtaining a sum greater than 10 or sum less than 5 =
36
3+6
=
4
1
Answered By
toppr
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Answer:
FIRST YOI HAVE TO KNOW THAT TO FIND THE PROBABILITY
=> I) 7/6 can't be divided so ans is 7/6
=> II) 10+6=16
=> 16/6. = 8/3 and
CAN YOU UNDESTAND IF YOU CAN'T THEN I CAN AGAIN MAKE U UNDERSTAND