Two dice are rolled together. Find the probability of getting a doublet or sum of faces as
4.
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Answer:
The probability of getting a doublet or sum of faces is 1/3.
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Total outcomes when rolling 2 dice = 36
probability of getting doublet = P(A)={(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}=6/36
probability of getting sum as 6=P(B)=
{(1,5),(2,4),(3,3),(4,2),(5,1)}=5/36
probability of getting a doublet and
total of 6 is P(A∩B)={(3,3)}=1/36
probability of getting a doublet or a
total of 6=P(A∪B)=P(A)+P(B)−P(A∩B)
=6/36+5/36−1/36
=10/36=5/18
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