Question

two dice are rolled together .Find the probability of getting:
(a) a total of at least 10.
(b) a multiple of 2 on one die and an odd number on the other die

Answer 1

a) 4,6)(5,6)(6,6)(6,4)(6,5)
so 5/36

b) (2,1)(2,3)(2,5)(4,1)(4,3)(4,5)(6,1)(6,3)(6,5) and inverse
so 18

so 18/36 = 1/2

Answer 2

two dice are rolled togather then
/S/=36
(a)let A be the incident that the total at least 10
then A=(4,6)(5,5)(6,6)(6,4)(6,5)(5,6)
p(A)=/A///S/
=6/36=1/6
(b)let B be the incident that a multiple of 2 on one die and an odd number on other die
B=(2,1)(2,3)(2,5)(4,1)(4,3)(4,5)(6,1)(6,3)(6,5)and inverse
/B/=18
p(B)=/B///S/
=18/36=1/2