TWO DICE ARE ROLLED TOGETHER. FIND THE PROBABILITY OF GETTING SUCH ON TWO DICE WHOSE PRODUCT IS PERFECT SQUARE.
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(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
Total outcomes = 36
Favourable outcomes of getting a product which is a perfect square = 8 [ (1, 1), (1, 4), (2, 2), (3, 3), (4, 1), (4, 4), (5, 5), (6, 6) ]
P ( x ) = Favourable outcomes / Total outcomes
P ( getting a perfect square ) = 8 / 36 = 1 / 4
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
Total outcomes = 36
Favourable outcomes of getting a product which is a perfect square = 8 [ (1, 1), (1, 4), (2, 2), (3, 3), (4, 1), (4, 4), (5, 5), (6, 6) ]
P ( x ) = Favourable outcomes / Total outcomes
P ( getting a perfect square ) = 8 / 36 = 1 / 4
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