Two dice are rolled together . Write the sample space . Find the probability of getting a doublet and even number in both dice and sum as 10 and number 2 in the first die
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Answer:
given below:
Step-by-step explanation:
when two dice are rolled,
n(S)=36
doublet=(1,1)(2,2)(3,3)(4,4)(5,5)(6,6)
P(doublet)=6/36=1/6
even on both dice=(2,2)(2,4)(2,6)(4,2)(4,4)(4,6)(6,2)(6,4)(6,6)
P(even)=9/36=1/4
sum as 10=(4,6)(5,5)(6,4)
=3/36=1/12
number 2 on first die=(2,1)(2,2)....(2,6)
=6/36=1/6
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