Two dice are through to same time and products of the number , apparing on them is noted find probability that the product is prime number
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S= (1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
n(S)=36
Suppose event A= product is prime no.
A=(1,2),(1,3),(1,5),(2,1),(3,1),(5,1)
n(A)=6
∴P(A)=n(A)/n(S)
=6/36
=1/6
(note-curly brackets are not in my keyboard, please add them)
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