two dice are thrown 500 times simultaneously and recorded sum is equal to 2 3 4 5 6 7 8 9 10 11 12 frequency is equal to 1430 42 5572 7570 5346 2815 if the dice are thrown once more what is the probability of getting a sum 3 more than 10 less than equal to 5 or between 8 and 12
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Step-by-step explanation:
total number of trials= 500
(1) P( sum more than 10 )=
28+15/500=43/500=0.086
(2) P( sum between 8 and 12)
=53+46+28/500=127/500=0.254
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