Question

Two dice are thrown 525 times simultaneously. Each time sum of two numbers appearing on top is noted and recorded as given in following table: Sum. Frequency 2. 24 3. 25 4. 62 5. 45 6. 42 7. 70 8. 70 9. 63 10. 46 11. 28 12. 50 Find probability of getting a sum (a) of 9 (b) less than or equal to six (c) which is multiple of 4 (d) which is perfect square I will mark as brain liest plz give appropriate answer

Answer 1

✨✨✨✨If we rolled dice around 520 times then it can be considered as its expected outcome, hence the probability of obtaining more than 10 as sum (28+15)/500=0.086.✨✨✨✨

Answer 2

Answer:

HOPE IT WILL HELP YOU............

PLEASE MARK IT AS BRAINLIEST.........................

Step-by-step explanation:

Given :

Sum of numbers 2 3 4 5 6 7 8 9 10 11 12

Frequency            20 16 28 18 24   22   52    66 48 38     68

And We know Probability P ( E ) = Total number of desired events n ( E )/Total number of events n ( S )

So,

Here Total number of events  =  Total number of times two dices thrown  =  n ( S ) =  400

And

To find  , probability of getting a sum of which is multiple of  2 , So

Total number of desired events  n ( E ) =  20 + 28  + 24  + 52  + 48 + 68 =  240

Then

Probability of getting a sum of which is multiple of  2 = 240/400 = 3/5                                  ( Ans )

And

To find  , probability of getting a sum of which is prime number  , So

Total number of desired events  n ( E ) =  20 + 16  + 18  + 22  + 38   =  114

Then

Probability of getting a sum of which is prime number  = 114/400 = 57/200   ( Ans )

And

To find  , probability of getting a sum of which is less than 4  , So

Total number of desired events  n ( E ) =  20 + 16   =  36

Then

Probability of getting a sum of which is less than 4  = 36/400 = 9/100                 ( Ans )