Question

two dice are thrown at a same time find the probability that the sum of two numbers appearing on the top of the dice is greater than 6 but less than 9 . explain the answer also plzzzzzzzz fast

Answer 1

1+6
2+5
2+6
3+4
3+5
4+3
4+4
5+2
5+3
6+1
6+2
this r the no. which r grater than 6 but less tha 9 so total no. =11
probability=11/36(36 is total amount of outcome of dice)

Answer 2

Answer:

The probability is 0.31

Step-by-step explanation:

Given that two dice are thrown at a same time.

we have to find the probability that the sum of two numbers appearing on the top of the dice is greater than 6 but less than 9.

Total outcomes are 36 which are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now favourable outcomes are those in which the sum of two numbers appearing on the top of the dice is greater than 6 but less than 9.

(1,6), (2,5), (2,6), (3,4), (3,5), (4,3), (4,4), (5,2), (5,3), (6,1), (6,2)

Favorable outcomes=11

$Probability=\frac{\text{Favourable outcomes }}{\text{Total number of outcomes }}$

$=\frac{11}{36}=0.3055\sim 0.31$

Hence, the probability is 0.31