Math, asked by samiyailyaskureshi, 2 months ago

Two dice are thrown at same time find the probability of given
situation.
a)the product of numbers appearing is 9.
b)5 will come atleast once.
c)Both the die has same number.
d)sum of both numbers is even.
c)The multiplication of both number is divisible by 3.​

Answers

Answered by sam262005
0

Answer:

Total no.of possible outcomes = 6^2 = 36

i.e. (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

Out of these,product of outcomes that would be prime would be (1,2),(1,3),(1,5),(2,1),(3,1),(5,1).

Probability = 6/36 = 1/6

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