Question

two dice are thrown at the same time and the product of numbers appearing on them is noted .find the probability that the product is less than 9

Answer 1

GIven that two dice are rolled.

Then the probability of outcomes n(S) = 6 * 6

                                                                 = 36.

Let E be the event of getting a product less than 9.

The number whose product is less than 9 

= {1,1},{1,2},{1,3},{1,4},{1,5},{1,6},{2,1},{2,2},{2,3},{2,4}{3,1},{3,2},{4,1},{4,2},{5,1},{6,1}

= 16.


Therefore the required probability

P(E) = n(E)/n(S)

        = 16/36

        = 4/9.


Hope this helps!

Answer 2

Answer:

GIven that two dice are rolled.

Then the probability of outcomes n(S) = 6 * 6

                                                                = 36.

Let E be the event of getting a product less than 9.

The number whose product is less than 9 

= {1,1},{1,2},{1,3},{1,4},{1,5},{1,6},{2,1},{2,2},{2,3},{2,4}{3,1},{3,2},{4,1},{4,2},{5,1},{6,1}

= 16.

Therefore the required probability

P(E) = n(E)/n(S)

       = 16/36

       = 4/9.

Hope this helps

Step-by-step explanation: