Math, asked by rishit999, 11 months ago

Two dice are thrown at the same time. Find the probability that the sum of the two numbers appearing on the top of the dice is (i)8 , (ii)13, (iii)less than or equal to 12.​

Answers

Answered by priyesh7654804695
0

Answer:

(I) 5/36

Step-by-step explanation:

Two dice are thrown at random then number of possible outcome are ( 1,1 ) ; ( 1,2 ) ; ( 1,3 ) ; ( 1,4 ) ; ( 1,5 ) ; ( 1,6 ) and so on to ( 6,6 ) .

Number of outcomes whose sum is 8 = 5

Probability ( getting sum 8 ) = 5/36

Answered by prajapatiravi
6

Answer:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

I) 8

p(A)=probability of getting 8

P(E)=No. of favourable outcome/No. of total outcome

p(A)=5/36

ii) 13

p(B)=probability of getting 13

P(E)=No. of favourable outcome/No. of total outcome

p(B)=0

iii) p(C)=probability of getting less than or equal to 12

P(E)=No. of favourable outcome/No. of total outcome

p(C)=36/36

p(C)=1

Step-by-step explanation:

hope It's helpful to you

Similar questions