Math, asked by rishit999, 8 months ago

Two dice are thrown at the same time. Find the probability that the sum of the two numbers appearing on the top of the dice is (i)8 , (ii)13, (iii)less than or equal to 12.​

Answers

Answered by priyesh7654804695
0

Answer:

(I) 5/36

Step-by-step explanation:

Two dice are thrown at random then number of possible outcome are ( 1,1 ) ; ( 1,2 ) ; ( 1,3 ) ; ( 1,4 ) ; ( 1,5 ) ; ( 1,6 ) and so on to ( 6,6 ) .

Number of outcomes whose sum is 8 = 5

Probability ( getting sum 8 ) = 5/36

Answered by prajapatiravi
6

Answer:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

I) 8

p(A)=probability of getting 8

P(E)=No. of favourable outcome/No. of total outcome

p(A)=5/36

ii) 13

p(B)=probability of getting 13

P(E)=No. of favourable outcome/No. of total outcome

p(B)=0

iii) p(C)=probability of getting less than or equal to 12

P(E)=No. of favourable outcome/No. of total outcome

p(C)=36/36

p(C)=1

Step-by-step explanation:

hope It's helpful to you

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