Two dice are thrown at the same time. Find the probability of getting multiple of 36 on the dice
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Answer:
1/36
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T( O) = 36
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
E= getting the multiple of 36
P(E) = no.of outcomes favourable at E / Total no. of possible outcomes
F(O) = 1 {36}
P(E) = 1/36
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