Question

Two dice are thrown at the same time. Find the probability of
a) Getting at least 9 as the sum
b) Not getting 5 on either dice.

Answer 1

HERE IS YOUR ANSWER ⬇⬇

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GIVEN : TWO DICES ARE THROWN AT THE SAME TIME

SAMPLE SPACE = { (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

TOTAL NUMBER OF OUTCOMES = 36

a) FAVOURABLE EVENT = (3,6) (4,5) (4,6) (5,4) (5,5) (5,6) (6,3) (6,4) (6,5) (6,6)

PROBABILITY OF GETTING AT LEAST 9 AS THE SUM

= NUMBER OF FAVOURABLE EVENT / TOTAL NUMBER OF OUTCOMES

= 10 / 36

= 5 / 18

b) FAVOURABLE EVENT = (1,1) (1,2) (1,3) (1,4) (1,6) (2,1) (2,2) (2,3) (2,4) (2,6) (3,1) (3,2) (3,3) (3,4) (3,6) (4,1) (4,2) (4,3) (4,4) (4,6) (6,1) (6,2) (6,3) (6,4) (6,6)

PROBABILITY OF NOT GETTING 5 ON EITHER DICES

= NUMBER OF FAVOURABLE EVENT / TOTAL NUMBER OF OUTCOMES

= 25 / 36

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HOPE IT HELPS